4(x^3-3)/(7x^2-8)

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Solution for 4(x^3-3)/(7x^2-8) equation: 


D( x )

7*x^2-8 = 0

7*x^2-8 = 0

7*x^2-8 = 0

7*x^2 = 8 // : 7

x^2 = 8/7

x^2 = 8/7 // ^ 1/2

abs(x) = (8/7)^(1/2)

x = (8/7)^(1/2) or x = -(8/7)^(1/2)

x in (-oo:-(8/7)^(1/2)) U (-(8/7)^(1/2):(8/7)^(1/2)) U ((8/7)^(1/2):+oo)

(4*(x^3-3))/(7*x^2-8) = 0

( 4 )

4 = 0

x belongs to the empty set

( x^3-3 )

1*x^3 = 3 // : 1

x^3 = 3

x^3 = 3 // ^ 1/3

x = 3^(1/3)

x = 3^(1/3)

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